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Class 10 Mathematics - Chapters 1-4

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110 original MCQs with answers and worked explanations, aligned with NCERT Class 10 Mathematics: Real Numbers (20), Polynomials (30), Pair of Linear Equations in Two Variables (30), Quadratic Equations (30).

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31. Chapter 2: Polynomials · mcq

Which polynomial has two real zeroes that are reciprocals of each other?

A.

2x2−7x+42x^2-7x+4

B.

2x2−7x+12x^2-7x+1

C.

2x2−7x+22x^2-7x+2

D.

2x2−7x−22x^2-7x-2

Show answer and explanation

2x2−7x+22x^2-7x+2

Reciprocal zeroes have product 1. For 2x2−7x+22x^2-7x+2, the product is c/a=2/2=1c/a=2/2=1, and its discriminant is 49−16=33>049-16=33>0, so both zeroes are real.

32. Chapter 2: Polynomials · mcq

For what value of k does x2−6x+kx^2-6x+k have both zeroes equal to 3?

A.

3

B.

6

C.

-9

D.

9

Show answer and explanation

9

A monic polynomial with zeroes 3 and 3 is (x−3)2=x2−6x+9(x-3)^2=x^2-6x+9. Thus k=9k=9.

33. Chapter 2: Polynomials · mcq

The graph of a polynomial meets the x-axis at exactly three distinct points. How many distinct real zeroes does it have?

A.

3

B.

0

C.

1

D.

2

Show answer and explanation

3

A real zero is an x-coordinate at which the graph meets the x-axis. Three distinct meeting points therefore give three distinct real zeroes.

34. Chapter 2: Polynomials · mcq

The graph of a polynomial does not meet the x-axis. How many real zeroes does the polynomial have?

A.

Infinitely many

B.

0

C.

1

D.

2

Show answer and explanation

0

A real zero requires the graph to meet the x-axis. Since there are no such points, the polynomial has no real zeroes.

35. Chapter 2: Polynomials · mcq

What is the maximum possible number of distinct real zeroes of a quadratic polynomial?

A.

1

B.

3

C.

2

D.

0

Show answer and explanation

2

A nonzero polynomial of degree 2 has at most two distinct zeroes. For example, x² - 1 has the two zeroes -1 and 1.

36. Chapter 2: Polynomials · mcq

Which monic quadratic polynomial has sum of zeroes 4 and product of zeroes -5?

A.

x2+4x−5x^2+4x-5

B.

x2−5x+4x^2-5x+4

C.

x2−4x+5x^2-4x+5

D.

x2−4x−5x^2-4x-5

Show answer and explanation

x2−4x−5x^2-4x-5

For sum SS and product PP, the monic polynomial is x2−Sx+Px^2-Sx+P. Substituting S=4S=4, P=−5P=-5 gives x2−4x−5x^2-4x-5.

37. Chapter 2: Polynomials · mcq

One zero of x2−9x+20x^2-9x+20 is 4. What is the other zero?

A.

5

B.

-5

C.

4

D.

9

Show answer and explanation

5

The sum of the zeroes is 9. If one is 4, the other is 9−4=59-4=5. The product check is 4×5=204\times5=20.

38. Chapter 2: Polynomials · mcq

The zeroes of x2−6x+8x^2-6x+8 are α,β\alpha,\beta. Find α2+β2\alpha^2+\beta^2.

A.

36

B.

20

C.

12

D.

28

Show answer and explanation

20

Here α+β=6\alpha+\beta=6 and αβ=8\alpha\beta=8. Thus α2+β2=(α+β)2−2αβ=36−16=20\alpha^2+\beta^2=(\alpha+\beta)^2-2\alpha\beta=36-16=20.

39. Chapter 2: Polynomials · mcq

The zeroes of x2−5x+6x^2-5x+6 are α,β\alpha,\beta. Find (α−β)2(\alpha-\beta)^2.

A.

13

B.

25

C.

1

D.

5

Show answer and explanation

1

α+β=5\alpha+\beta=5 and αβ=6\alpha\beta=6. Therefore (α−β)2=(α+β)2−4αβ=25−24=1(\alpha-\beta)^2=(\alpha+\beta)^2-4\alpha\beta=25-24=1.

40. Chapter 2: Polynomials · mcq

The zeroes of x2−3x−4x^2-3x-4 are α,β\alpha,\beta. Find 1α+1β\frac1\alpha+\frac1\beta.

A.

34\frac34

B.

−43-\frac43

C.

43\frac43

D.

−34-\frac34

Show answer and explanation

−34-\frac34

The zeroes are nonzero because their product is -4. Hence 1/α+1/β=(α+β)/(αβ)=3/(−4)=−3/41/\alpha+1/\beta=(\alpha+\beta)/(\alpha\beta)=3/(-4)=-3/4.