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Class 10 Mathematics - Chapters 1-4

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110 original MCQs with answers and worked explanations, aligned with NCERT Class 10 Mathematics: Real Numbers (20), Polynomials (30), Pair of Linear Equations in Two Variables (30), Quadratic Equations (30).

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Chapter 1: Real NumbersAll chapters

20 ready questions · 10 per page

11. Chapter 1: Real Numbers · mcq

Which of the following is irrational?

A.

154\frac{15}{4}

B.

0.75

C.

2+52+\sqrt{5}

D.

81\sqrt{81}

Show answer and explanation

2+52+\sqrt{5}

If 2+52+\sqrt{5} were rational, subtracting the rational number 2 would make 5\sqrt{5} rational, which is impossible. The other choices are rational.

12. Chapter 1: Real Numbers · mcq

What can be said about the sum of a rational number and an irrational number?

A.

It is always rational

B.

It is always an integer

C.

It is always zero

D.

It is always irrational

Show answer and explanation

It is always irrational

If the sum were rational, subtracting the original rational number would make the irrational number rational. This contradiction proves that the sum is irrational.

13. Chapter 1: Real Numbers · mcq

Which expression equals 18\sqrt{18}?

A.

323\sqrt{2}

B.

929\sqrt{2}

C.

232\sqrt{3}

D.

9

Show answer and explanation

323\sqrt{2}

18=9×2=32\sqrt{18}=\sqrt{9\times2}=3\sqrt{2}. Since 2\sqrt{2} is irrational, so is 18\sqrt{18}.

14. Chapter 1: Real Numbers · mcq

Which number below is irrational?

A.

1.25

B.

12\frac{1}{\sqrt{2}}

C.

12\frac{1}{2}

D.

16\sqrt{16}

Show answer and explanation

12\frac{1}{\sqrt{2}}

1/2=2/21/\sqrt{2}=\sqrt{2}/2. A nonzero rational multiple of 2\sqrt{2} is irrational. The other three choices are rational.

15. Chapter 1: Real Numbers · mcq

Can 6n6^n end in the digit 0 for a positive integer nn?

A.

Yes, whenever n is a multiple of 5

B.

Yes, for every n greater than 1

C.

No, its units digit is always 6

D.

Yes, for every even n

Show answer and explanation

No, its units digit is always 6

6n=2n3n6^n=2^n3^n has no factor 5, whereas a number ending in 0 must be divisible by 10=2×510=2\times5. In fact, every positive power of 6 ends in 6.

16. Chapter 1: Real Numbers · mcq

Three ropes measure 96 m, 120 m and 168 m. They must be cut into equal pieces of the greatest possible length, with no waste. How long is each piece?

A.

12 m

B.

36 m

C.

48 m

D.

24 m

Show answer and explanation

24 m

The greatest length that divides all three measurements is their HCF. HCF(96, 120, 168) = 24, so each piece is 24 m long.

17. Chapter 1: Real Numbers · mcq

Three bells ring at intervals of 12, 15 and 20 minutes. They ring together now. After how many minutes will they next ring together?

A.

60 minutes

B.

30 minutes

C.

120 minutes

D.

240 minutes

Show answer and explanation

60 minutes

The next common ringing time is LCM(12, 15, 20). The LCM is 60, so they next ring together after 60 minutes.

18. Chapter 1: Real Numbers · mcq

What is the smallest positive integer divisible by 8, 12 and 18?

A.

144

B.

72

C.

36

D.

48

Show answer and explanation

72

The required number is their LCM. Since 8=238=2^3, 12=22×312=2^2\times3 and 18=2×3218=2\times3^2, the LCM is 23×32=722^3\times3^2=72.

19. Chapter 1: Real Numbers · mcq

Find the HCF of 23×322^3\times3^2 and 22×33×52^2\times3^3\times5.

A.

72

B.

180

C.

36

D.

18

Show answer and explanation

36

Only 2 and 3 are common prime factors. Taking their smaller exponents gives 22×32=362^2\times3^2=36.

20. Chapter 1: Real Numbers · mcq

In a proof by contradiction, suppose 3=a/b\sqrt{3}=a/b, where a and b are coprime integers and b is nonzero. Which conclusion contradicts coprimality?

A.

Only a is divisible by 3

B.

Both a and b are nonzero

C.

The square of a is positive

D.

Both a and b are divisible by 3

Show answer and explanation

Both a and b are divisible by 3

Squaring gives a2=3b2a^2=3b^2, so 3 divides aa. Write a=3ka=3k; then b2=3k2b^2=3k^2, so 3 also divides bb. This contradicts the assumption that aa and bb are coprime.